Question

Solve the equation after making an appropriate substitution.
\(\sqrt{p}-2\sqrt[4]{p}-8=0\)

Answer 1

Oh sorry .. actually, let \(y= \sqrt[4]{p}=p^{1/4}\)
Then you have \(y^2-2y-8=0\)

Answer 2

\(\sqrt{p}-2\sqrt[4]{p}-8=0\)
was the question.