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Algebra 19 Online
OpenStudy (anonymous):

can you help me solve: |x| < 2? A. x < 2 B. -2 < x < 2 C. x > -2 D. x < 0

OpenStudy (phi):

change |x| < 2 to two problems: x < 2 and -x < 2 the first problem is done: x<2 is part of the answer for -x< 2 add +x to both sides -x+x < x + 2 or 0 < x + 2 now add -2 to both sides -2 < x that is the other part of the answer

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

you can also graph it to see what is going on...|dw:1410888905804:dw| where is the graph of y = |x| < 2? That is, for what values of x will |x| < 2?

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