A projectile is thrown upward so that its distance is above the ground after t seconds is given by the function h(t)=-16^2+576t. After how many seconds does the projectile reach its maximum height?

Question

bradely · Answer

For maximum height dh/dt =0 -32t+576=0 t=18 sec Source: http://www.mathskey.com/question2answer/

anonymous · Answer

@bradely Can you show me step by step how to work it out? i dont understand how you got that. Thanks for the help :)

anonymous · Answer

I stated the question wrong its is h(t)=16t^2+576t