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3x^2+27x+9
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are you factoring this
\[-b \pm \sqrt{b ^{2}-4ac}/2a\]
3x^2+27x+9(divide by 3) x^2+9x+3 a=1,b=9 and c=3 substitute the values
Yes. The worksheet says to factor out the GCF.
How do you get 9x?
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he is Apply the Quadratic Formula and factoring
if you have to factor\[3x^2+27x+9\]need to divide everything by 3 so you would get\[3(x^2+9x+3)\]
Why apply the Quadratic Formula? And what is the Quadratic Formula?
Oh yeah, now I get where the 9x came from, just needed to see it written out and then it clicked in my head.
So now do I distribute the 3 or do I simplify?
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