Question

Finding the limit of an equation involving tan and sin.

Answer 1

\[\lim_{x \rightarrow 0}\frac{ \tan 6x }{ \sin 2x }\]

Answer 2

since you get 0/0, i would use L'Hopitals rule if you have learned derivatives
after differentiating:
\[\lim_{x \rightarrow 0}\frac{6\sec^2 (6x)}{2\cos(2x)} = 3\]