Question

write the equation of the line with the slope of -3 and through points (5, -8)

Answer 1

The general linear equation in slope intercept form is y = mx+b

m is the slope
b is the y-intercept

Answer 2

y = mx+b

y = -3x+b ... plug in the slope of -3

-8 = -3*(5) + b ... plug in the given point (x,y) = (5,-8)

now we solve for b

-8 = -3*(5) + b

-8 = -15 + b

-8 + 15 = b

7 = b

b = 7

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So we know that m = -3 and b = 7

Therefore, y = mx+b turns into y = -3x + 7