Question

Hi everybody i am trying to understand very well how work this program line by line. please help me


1)cubex = int(raw_input('Enter an integer: '))
2)for ans in range(0, abs(x)+1):
3) if ans**3 == abs(x):
4) break
5)if ans**3 != abs(x):
6) print x, 'is not a perfect cube'
7)else:
8) if x < 0:
9) ans = -ans
10)print 'Cube root of ' + str(x) + ' is ' + str(ans)


when the program reach at the line 3 and if the condition is true, it go to te line 4 to break to for loop, and what happen next?
Python is a indented language so that mean it will execute de line 5 too, but in the case it got the true for the line 3, i think the next take should be the line 7!
please if someone call help me to understand better this, i would be thankful!

Answer 1

First, use \(\text{```}\) above and below a block of code to keep proper formatting when you post it here. See what it does to yours:
```
x = int(raw_input('Enter an integer: '))
for ans in range(0, abs(x)+1):
if ans**3 == abs(x):
break
if ans**3 != abs(x):
print x, 'is not a perfect cube'
else:
if x < 0:
ans = -ans
print 'Cube root of ' + str(x) + ' is ' + str(ans)
```
Nice and clean.

OK, so first you take in a number.
You do a for range to test the integers from 0 to the absolute value of the input.
The break stops the for loop if things were found.
The next if is for when the input is -1, 1, or 0.
The else is to test for negative numbers in situations other that -1, 1, or 0.
Finally you print out the cube root result no matter what.

Answer 2

If line 3 is true, the loop breaks, and line 5 is executed. Line 5 is not part of the for loop.

Answer 3

thatś right,
but the condition is not true
so next is 7 and then 8, which might or might not be true
and then the final print is done

I think the last print statement should be under the if statement
else:
else:
if x < 0:
ans = -ans
print 'Cube root of ' + str(x) + ' is ' + str(ans)