Question

4x^2+1.5x+1=22.5

Answer 1

Equations is: \(4x^2+1.5x+1=22.5\)
Put the \(22.5\) the the LHS\[4x^2+1.5x+1-22.5=0\]\[4x^2+1.5x-21.5=0\]
Where:\[a=4\]\[b=1.5\]\[c=-21.5\]
Us the quadratic equation:
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
Sub in the values:
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
\[x=\frac{-1.5\pm\sqrt{1.5^2-4*4*-21.5}}{2*4}\]
This will give you \(x\)
Do you understand, @maria_zahi?

Answer 2

@maria_zahi ?

Answer 3

Why is that not linking?