A part of Php8,900 is invested at 6% and the remainder at 4%. The annual income from 4% investment exceeds the income from the 6% investment by Php74. Represent the amount of each investment

Question

shinalcantara · Answer

let x be the amount invested @ 6%
    y be the amount invested @ 4%

     x+y = 8,900  ---eqn 1
     0.04y = 0.06x +74
       y = 1.5x + 1850  ----eqn 2
substitute eqn 2 to eqn 1
    x + 1.5x +1850 = 8,900
    2.5x = 8900 - 1850
         x = 2,820

 substitute to eqn 1
   2,820 + y = 8,900
    y = 8,900 - 2,820
    y = 6,080

anonymous · Answer

THANK YOU SO MUCH @shinalcantara