Question

-2/7 + 6 +1/7x = 18

Answer 1

Equation:\[\frac{-2}{7}+\frac{1}{7x}+6=18\]

Answer 2

Move the 6 over to the RHS
\[\frac{-2}{7}+\frac{1}{7x}=18-6\]\[\frac{-2}{7}+\frac{1}{7x}=12\]

Answer 3

Convert all of them to have a denominator of \(7x\)
\[\frac{-2}{7}*\frac{x}{x}+\frac{1}{7x}=\frac{12}{1}*\frac{7x}{7x}\]

Answer 4

\[\frac{-2x}{7x}+\frac{1}{7x}=\frac{84x}{7x}\]

Answer 5

Cancel out the \(7x\)\[-2x+1=84x\]

Answer 6

Solve for \(x\)
I might have made a miscalculation on the way, really busy right now. Sorry for that, but that is the jist of it.

Answer 7

ok