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What is the square root of 72x^3 divided by y^2
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\[\sqrt{72x ^3 \div y^2}\]
\[\frac{ 432\sqrt{2} }{ y }\]
72=9*8 =3*3*2*2*2 =(3^2)*(2^2)*2 now [\sqrt{72}\]=3*2*[\sqrt{2}\]
@judispute what is this ??
so exactly what is the anser of this question khurramshahzad 72=9*8 =3*3*2*2*2 =(3^2)*(2^2)*2 now [\sqrt{72}\]=3*2*[\sqrt{2}\]
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(6/y)*[\sqrt{2x}\]
sqrt(x3)=x*sqrt(x) sqrt(y2)=y
(6/y)*[\sqrt{2x}\] its answer
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