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Mathematics 17 Online
OpenStudy (anonymous):

2x(x-3)=5x^2-7x

OpenStudy (anonymous):

solve for \(x\) ?

OpenStudy (anonymous):

\[2x(x-3)=5x^2-7x\] multiply out and start with \[2x^2-6x=5x^2-7x\] then set it equal to zero

OpenStudy (anonymous):

subtract \(x^2\) and add \(6x\) to get \[3x^2-x=0\]

OpenStudy (anonymous):

factor to finish it

OpenStudy (anonymous):

you good from there?

OpenStudy (anonymous):

Ugh you're such great help! thank you so much

OpenStudy (anonymous):

@satellite73

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