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If quadrilateral ABCD rotates 90° counterclockwise about the origin, what are the coordinates of A′ in quadrilateral A′B′C′D′ ?
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(2, 1) (-2, -1) (-2, -2) (-2, 0)
sorry i suck with this stuff :(
but i will look
better have someone else look at it ;)
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OA and OA' will be perpendicular
so the product of their slopes will be equal to -1
m1 = -2 so m2 = 1/2 and A' point will be in third quadrant .. only option 2 satisfy this. and distance also remains the same .. which OA=OA'
distance from origin also doesnt change
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