In a photoelectric effect experiment, a beryllium surface (work function= 8.01 x 10^-19 J) is bombarded with photons from a 125 nm source of electromagnetic radiation.
a.) what is the energy of the incident photons?
b.) what is the maximum speed of electrons emitted from the berylliums surface?

Question

In a photoelectric effect experiment, a beryllium surface (work function= 8.01 x 10^-19 J) is bombarded with photons from a 125 nm source of electromagnetic radiation. 
a.) what is the energy of the incident photons?
b.) what is the maximum speed of electrons emitted from the berylliums surface?

aaronq · Answer

a)         $\huge E_{photon}=\dfrac{hc}{\lambda}$    (make sure these units match)


b)           $\huge  E_{photon}-\underbrace{\phi_0}_{\small Work function}=\dfrac{1}{2}m_ev^2$