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Mathematics 6 Online
OpenStudy (anonymous):

u=3i-j, v=i+aj, u and v are perpendicular determine the value of a to make conditions true

OpenStudy (anonymous):

dot product of perpendicular vectors is zero . so \[u.v = (3i-j) (i+aj) = 0\] \[3-a=0 \implies a = 3\]

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