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Evaluate each expression for x = -2 and y = 3 11. 6xy + 2x2 + 4x 12. (3x + y2)2
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6(-2)(3)+2(-2)2+4(-2) solve
(3(-2)+(3)2)2 solve
128 for the first one
make that -128
the 2nd is 0 because2*0=0
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thanks @jazzy688
your welcome itry to be the best
How did you get -128 for the first one? I got -52. Could you explain? Thanks!
I meant can you post the math as to how you arrived at your answer? Here's how I got -52, maybe you can show me where I went wrong. 6 * (-2) * 3 = -36 + 2 * (-2) * 2 = -8 + 4 * (-2) = -8 -36 + -8 + -8 = -52 Thanks
|dw:1411157313484:dw| we both are wrong miss calculations
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I think you left out a 2 here: (-2)2+4(-2) as it is 2* the Variable X * 2, not 2 x 2?
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