Question

odd function check please

Answer 1

So i did the f(-x)= -f(x) and got the same thing. would I be right then if this is true?

Answer 2

\[f(-x) = \dfrac{1}{2}(-x)^2+4 = \dfrac{1}{2}x^2+4\]Notice that we just got back to original equation [ f(-x) = f(x) ]

Answer 3

So it is even function

Answer 4

erg i got 1/2(x^2+8) T-T

Answer 5

\[-f(x) = -\left(\dfrac{1}{2}x^2+4\right) = -\dfrac{1}{2}x^2-4\]Not same as f(-x)

Answer 6

Does that confused you?

Answer 7

erggg again i missed the sign