Question

5r2 −44r+120=−30+11r

Answer 1

\[5r ^{2}-44r+120=-30+11r\]
\[5r ^{2} -44r - 11r +120 +30 = 0\]
\[5r ^{2} - 55r + 150 = 0\]
divide by 5
\[r ^{2} - 11r + 30 = 0\]
Now Factorize

Answer 2

\[r ^{2} - 5r-6r+30=0\]
\[r(r-5) -6(r-5) = 0\]
\[(r-5)(r-6) = 0\]