Question

Find the equation of the line through the intersection of the lines 3x+2y−8=0,5x−11y+1=0 and parallel to the line 6x+13y=25

Here is how I did it..

L1 = 3x + 2y -8 = 0, L2 = 5x -11y +1 = 0, L3= ? , L4 = 6x + 13y -25= 0

I found the point of intersection : (-2, -1)

Using formula: L1 + kL2 = 0

(3x + 2y -8) + k(5x -11y +1)=0

(3(2) + 2(1) -88) + k(5(2) -11(1) +1) = 0

(6 +2 -8) + k(10 -11 +1) =0

8-8 + k(11-11) =0

0 +k(0) = 0

What's wrong ?