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Mathematics 14 Online
OpenStudy (anonymous):

Use the function to answer the question. h : k -> k^2 - K What is the value of h(1)?

OpenStudy (anonymous):

How do I solve this problem?

OpenStudy (anonymous):

Will the new function be: \[1 : k -> k^2 - k\]?

OpenStudy (anonymous):

Looks like a transformation, I think it would just be k=1, so k^2-k=0

OpenStudy (anonymous):

I forget the exact notation of transformations though (been a while since I took Linear Algebra so don't hold me to it)

OpenStudy (anonymous):

Understandable. Thanks for trying.

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