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Calculus1
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find equation to tangent y=(pi*sqrt(x))/2 at x=1
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Have you considered the 1st Derivative?
^Beat me to it. Take the first derivative of your original equation, then f'(1) will give you the y-coordinate you need.
f(x+h) - f(x) f '(x) = Lim ─────── h→0 h this is the formula you can use. The result is the slope of the tangent line, and the point is just (1, f(1) )
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