Ask your own question, for FREE!
Chemistry 17 Online
OpenStudy (anonymous):

PLEASE SHOW ME HOW TO DO THIS A clinic took temperature readings of 250 flu patients over a weekend and discovered the temperature distribution to be Gaussian, with a mean of 102.00°F and a standard deviation of 0.5660. Use this normal error curve area table to find the following values. (a) What is the fraction of patients expected to have a fever greater than 103.58°F? (b) What is the fraction of patients expected to have a temperature between 101.43°F and 102.74°F?

OpenStudy (anonymous):

Basically the question is asking how far from the mean your data is. Gaussian functions are well known and easy functions to use, once you understand them. For instance the amount of data within the mean plus or minus the standard deviation (102.00-.5660 to 102+.5660) is 68%. You can use an error function table to figure out the percent inside a certain range of standard deviations. If you need the range outside you can subtract from 100.

OpenStudy (anonymous):

im still a little lost, can you show me how to apply the concept on this problem @pcaginalp

OpenStudy (aaronq):

this is statistics, ask in the math section

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Mari103: How to pop out like a Jacc In the box
39 minutes ago 0 Replies 0 Medals
Breathless: Spooky witch but cute
7 hours ago 3 Replies 0 Medals
Arriyanalol: help
7 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 4 Medals
Jaded012023: Please tell me what you all think of this song
10 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
10 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!