Question

Precal Help please

Answer 1

@kirbykirby I do not know how to multiply these 2 together for f*g and g*f

Answer 2

It's not multiplication. It is "of"

Answer 3

Isnt it the same thing though?

Answer 4

\[f(\color{red}{x})= 6-\color{red}{x}^2\]
so, if you find \(fog\), that means
\[f(\color{red}{g(x)})= 6-\color{red}{(g(x)})^2\]

Answer 5

Where you see x, replace by g(x)

Answer 6

You misunderstood the concept. It is NOT multiplication (Again)

Answer 7

alright sqrt 6= 6- sqrt 6 ^2?

Answer 8

replace the whole g(x) in
your g(x) = \(\sqrt 6 -x\)
so that
\[f(\color{red}{g(x)})= 6-\color{red}{(\sqrt6 -x)})^2\]

Answer 9

do some algebra to get the answer.

Answer 10

Like "father of father is grandfather, it's not \(father ^2\)