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help with integration!! calculate the area of the regions by the functions below:
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\[y=e^x-3e^ \frac{ x }{ 2}\] x=ln25 x=0 y=0
simply integrate it
e^x have integration e6x and e^x/2 willhave (e^x/2)/1/2
+ consant c
use the fact that \[\int\limits_{g(x)}^{f(x)}dt=f(x)-(g(x)\]
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|dw:1411386854917:dw| how do i solve for the x-int without the calculator?
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