Question

which value of b solves the equation

b^-3= 1/216

Answer 1

b^-3=1/b^3
\[\frac{ 1 }{b ^{3}}=\frac{ 1 }{ 216 }=\frac{ 1 }{ 6^3 }\]

Answer 2

6^3=b^3
6=b

Answer 3

tanks so much @gorv here is your medal and fan

Answer 4

welcome buddy :)