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OpenStudy (anonymous):
y=0.5x 2y=x+4
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OpenStudy (anonymous):
please help
OpenStudy (cj49):
?
OpenStudy (cj49):
y=0.5x
2y=x+4
wats the question
OpenStudy (anonymous):
i need to find the x and y using the substitution and the elimination method
OpenStudy (cj49):
y-0.5x=0
2y-x =4(0.5)
0.5y-0.5x=2
2y-0.5x=0
-1.5y=2
y=-2/1.5
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OpenStudy (cj49):
substitute y then ull get x
OpenStudy (anonymous):
its x+4
OpenStudy (cj49):
2y=x+4
2y-x=4
OpenStudy (anonymous):
2y=x+4
OpenStudy (anonymous):
you're confusing me more
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OpenStudy (cj49):
i get it but when u transfer x from the r.h.s to the l.h.s then the sign changes
OpenStudy (cj49):
to solve by elimination method this is the standard form x+y=0
here its 2y=x+4
so we need to transfer x from the rhs to the lhs
it wud be -x+2y=4
OpenStudy (anonymous):
you confused me more
OpenStudy (cj49):
how would u approach this problem
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OpenStudy (anonymous):
im just confused more and i dont know and u cant explain it
OpenStudy (cj49):
are u familiar with elimination method
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