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Mathematics 14 Online
OpenStudy (anonymous):

the answer of?

OpenStudy (anonymous):

\[[\frac{ 1 }{ 2} \ln (\infty)^{2}+1-(\frac{ 1 }{ 2} \ln (0)^{2}+1)\]

OpenStudy (anonymous):

the first part confused me ......-infinty+1

OpenStudy (anonymous):

is this right 0.5*infinty+1-0.5infinty+1

OpenStudy (anonymous):

if yes does it eual to zero

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