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Algebra
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Help please! Find a number that is greater than three times its opposite. Steps needed!
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\[x>-3x\] is what we want to solve can you solve this?
i dont understand this equation
\[x>-3x\] \[0>-2x\]\[0<x\]
Ok let x be the number then 3 times its opposite is -3x
so x>-3x "x is greater than -3x"
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okayyyy?
so any number larger than 0 will work
?
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