Question

solve the complex number system (x^3)-125=0 in a+bi form

Answer 1

do you recognize the difference of cubes?

Answer 2

a^3 - b^3 = (a - b)( a^2 + ab + b^2)

you can factor the quadratic ( a + b)^2 - ab =0 (a + b)^2= ab a + b = =/-sqrt ab

for this problem a = x and b = 5

Answer 3

well there is no complex solution if you rewrite it you get

\[x^3 = 125\]

so

x = 5

Answer 4

all you need to do is take the cube root of both sides

Answer 5

@campbell_st in a+bi form

factoring special products ----difference of cubes

I did something like this recently it has to to with the + and - root

Answer 6

@satellite73 will you please help

Answer 7

ok... I'd say

x = 5 + 0i