Question

What is the result of isolating y^2 in the equation below?
(x+6)^2 + y^2 = 1

A.) y^2 = -x^2 - 12x -35
B.) y^2 = x^2 + 12x + 37
C.) y^2 = -x^2 - 35
D.) y^2 = x^2 + 37

Help? Please?

Answer 1

(x+6)^2 + y^2 = 1

First, simplify.
x^2 + 12x + 36 + y^2 = 1

Next subtract x^2 from both side of the equation.
36 + 12x + y^2 = -x^2 +1

Next subtract 12x from both side of the equation.
36+ y^2 = -x^2 -12x

Next subtract 36 from both side of the equation.
y^2 = -x^2 -12x -35

Answer 2

Okay thanks.

Answer 3

No problem. :)