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OpenStudy (anonymous):
Mary is twice as old as Ann when Mary was as old as Ann is now. When Ann is as old as Mary, the sum of their ages is 180. Find the age of each now.
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OpenStudy (anonymous):
How do you solve this using linear/quadratic equation?
OpenStudy (shinalcantara):
|dw:1411477384548:dw|
OpenStudy (shinalcantara):
after finding the value of x, you may now substitute to find their ages at present :)
OpenStudy (anonymous):
Thanks!
OpenStudy (shinalcantara):
yw
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