Question

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the distance in 4 h. Car A traveled 22 mph faster than Car B.

How fast did Car A travel?


_____mph

Answer 1

You have the formula,
Velocity=distance/time
hence we'll use that to solve for the velocity of both Cars A and B
since Car A traveled for 2.4 hours, then we'll have
Va = d/2.4 -----equation 1
since Car B traveled for 4 hours, then,
Vb = d/4 -----equation 2
NOTE that the distance traveled by Cars A and B are equal
getting the distance from equations 1 & 2
Va = d/2.4
d=2.4Va -------equation 3
Vb = d/4
d=4Vb -------equation 4
since distance of A and B are equal then we can equate equations 3&4
2.4Va=4Vb ------equation 5
The problem states that Car A traveled 22mph faster than car B.
Therefore we'll have the equation as:
Va=Vb+22 -------equation 6
substituting equation 6 to equation 5 we'll have
2.4Va=4Vb
2.4(Vb+22)=4Vb
2.4Vb +22(2.4)=4Vb
4Vb-2.4Vb=52.8
1.6Vb=52.8
Vb=33mph
substituting Vb to equation 6
Va=Vb+22
Va=33+22
Va=55mph

Answer 2

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