Question

How to integrate (z+1)/(z-1)^2 dz?

Answer 1

@ParthKohli @Abhisar @Destinymasha

Answer 2

partial fractions

Answer 3

@dumbcow

Answer 4

lets see i think a simple substitution will work here as well

u = z - 1
du = dz
--> z+1= (u+1)+1 = u+2

\[\int\limits \frac{u+2}{u^2} du = \int\limits \frac{1}{u} + 2 u^{-2}\]

Answer 5

Thank you, @dumbcow