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write an equation of the line that passes through the point (6 2) and is perpendicular to y= 3x + 3
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slope is 3 y-y1=3(x-x1) y-2=3(x-6)
thank you very much
yw c:...ull need to simplify it
okay thanks
\(\Huge\cal\color{blue}{?-?}\)
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just a minute the slope would not be 3
parallel lines have the same slope but this line is perpendicular. for perpendicular lines the product of the slopes = -1
y=mx+c
slope = -1/m= -1/3 points (6, 2) and (x, y) equation y-2 = -1/3(x - 6) point slope format y = -1/3 x + 4 slope intercept format
@tabithachambers
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