The length of a rectangle is six times its width.
If the area of the rectangle is 600 cm2 , find its perimeter.

Question

The length of a rectangle is six times its width. 
If the area of the rectangle is 600 cm2 , find its perimeter.

anonymous · Answer

To make this problem easier, draw a rectangles. Label the length 6w because it is 6 times the width. Label width w. Then set up an equation that says length times width = area. This is the equation: 6w*w=384. Multiply, you get 6w^2=384, divide both sides by six, you get w^2=64, then take the square root of both sides, so sqrtw^2=sqrt64. x=8. Width is 8 and the length is 48! Then add all sides, 8+8+48+48=112.

anonymous · Answer

im a nerd

anonymous · Answer

since when is $8\times 48=600$ ?

anonymous · Answer

copy and paste from some other problem i guess, but the idea is right
equation should be 
$$6w^2=600$$ making $w^2=100$ and so $w=10$

anonymous · Answer

The perimeter is:
   2 w + 2 (6 w)
           at w = 10,
   20 + 120 = 140

anonymous · Answer

Thank you ! Can you please help me with another one?

anonymous · Answer

y you block me