Question

-1 × (-19 + |-33|) + 6

Answer 1

Use the rule PEMDAS to simplify

Answer 2

|+x| = x
|-x| = x

Answer 3

Helping my son been out of school 20+ yrs....idk what that is

Answer 4

okay ... so what is |-33| = ?

Answer 5

I just need to know what to do with the I-33I

Answer 6

That's what I'm stuck on

Answer 7

|-x| = x
|-33| = ?
so,

Answer 8

33??

Answer 9

yeah

Answer 10

Modulus of any number(positive or negative) is always POSITIVE

Answer 11

So the answer is -14

Answer 12

I forgot the +6

Answer 13

-14 + 6 = -8

Answer 14

Right...I missed a step...thanks

Answer 15

yeah.. My pleasure... :)

Answer 16

@midhun.madhu1987 you are wrong.....

Answer 17

but your sign convention is true,that it is always be positive

Answer 18

see when we open modulus,there will be 2 sign one is +ve and other is -ve,but the value should always be +ve

Answer 19

Yikes!

-1 × (-19 + |-33|) + 6

Reconcile Absolute Values

-1 × (-19 + 33) + 6

Reconcile parentheses

-1 × 14 + 6

Multiplication

-14 + 6

Addition

-8

Answer 20

|x| = x IF x > 0
|x| = -x IF x < 0

Answer 21

like :-
\[\large \bf \left| x \right|---->+x~and~-x\]

Answer 22

yes,@tkhunny is right

Answer 23

but we know the value of x i.e 33 which is constant value,then we open with this :-
\[\large \bf \left| -33 \right|=-(-33)=+33\]

Answer 24

|-x| = x IF x > 0
|-x| = -x IF x < 0

Answer 25

thats why,when we open modulus,the value become +ve

Answer 26

hope you understand. @midhun.madhu1987

Answer 27

yep

Answer 28

great

Answer 29

This was incorrect:

|-x| = x

If x < 0, that is not the correct result.

Answer 30

\[\large \bf \left| x \right|=-x~where~x<0\]