solve the equation for F in terms of Y C=5/9(f-32)
What's y supposed to be?
sorry i ment F in terms of C
Okay, you need the value for f.. Do they give the temperature in F?
no
the topic is supposed to be rewriting equations
Okay you multiply both sides by nine, to clear out the denominator. Then divide both sides by 5. Then add the 32 to both sides.
but arent u supposed to do the distributive property since f-32 are in parentheses
No because you are isolating the f and turning the equation around and moving everything to the other side..
can you type your work so i can understand better
\[C=\frac{ 5 }{ 9 }(f-32)\] \[9\times C=\frac{ 5 }{ 9 }(f-32)\times9\] \[9\times C=5\times(F-32)\] \[\frac{ 9C }{ 5 }=\frac{ 5\times(F-32) }{ 5 }\] \[\frac{ 9 }{ 5 } \times C=F-32\] \[\frac{ 9 }{ 5 } \times C + 32=F-32+32\] \[F=\frac{ 9 }{ 5 } \times C=32\]
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