Question

Choose the value for x that makes the open sentence true.
6 ● 7 – 5x + x2 ≥ x3 + x2

Answer 1

Do you have choices? @Jojoplayz12

Answer 2

Yea

Answer 3

Okay, can you post them?

Answer 4

3
4
5
6

Answer 5

\(6 ● 7 – 5x + x^2 ≥ x^3 + x^2\)

Lets plug in 3:

\(6 ● 7 – 5(3) + 3^2 ≥ 3^3 + 3^2\)

Multiply -5 * 3:

\(6 ● 7 – 15 + 3^2 ≥ 3^3 + 3^2\)

Simplify all exponents:

\(6 ● 7 – 15 + 9 ≥ 27 + 9\)

Multiply 6 * 7:

\(42 – 15 + 9 ≥ 27 + 9\)

Subtract 42 - 15:

\(27 + 9 ≥ 27 + 9\)

Add 27 + 9:

\(36 ≥ 27 + 9\)

Add 27 + 9:

\(36 ≥ 36\)

So 3 is correct.

Answer 6

Thanks So much IGreen!

Answer 7

Welcome to Open Study!

You can give medals by clicking 'Best Response'. @Jojoplayz12

Answer 8

:D

Answer 9

If you see these black diamonds '��', then just click on a different post and click back in.

Answer 10

No problem!