Question

HELP HELP HELPY HELP HELP IM STUCK ON THIS MATH PROBLEM I NEED ASSISTANCE!! I give SHINEY MEDAL AND I WILL BECOME YOUR FAN

Answer 1

@cj49 @amistre64 @tester97

Answer 2

sorry mate m not good with functions and graph

Answer 3

S(t) = t^2 + 6t + 48
S is sales in millions of dollars
t is the year since 1995.

You get y-intercept by setting t = 0. And t = 0 represents the year 1995.
when t = 0, S(t) = 0 + 0 + 48
The y-intercept represents the sale in millions of dollars in the year 1995 and it is $48 million.

Answer 4

Thx soo much

Answer 5

B) The domain refers to the value of t. Since t = 0 represents the year 1995 and the model applies only for the years 1995 to 2004, the domain of t is: 0 to 2004-1995 = 9.
The domain of the function in interval notation is: [0, 9]

Answer 6

C) Average rate of change of a function S(t) from t = a to t = b is:\[
\frac{S(b) - S(a)}{b - a}
\]Here they wan the average rate of change from the first year to the fourth year. In this model t = 0 represents the first year and t = 3 represents the fourth year because the counting of the year starts from zero instead of one. So the average rate of change = \[
\frac{S(3) - S(0)}{3 - 0} = ?
\]

Answer 7

3? @aum

Answer 8

S(t) = t^2 + 6t + 48
S(3) = 3^2 + 6(3) + 48 = 9 + 18 + 48 = 75
S(0) = 0 + 0 + 48 = 48
S(3) - S(0) = 75 - 48 = 27

denominator: 3 - 0 = 3

27/3 = 9