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Given f(x)=2x-2/4, solve for f^-1(3).
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@nincompoop
translate as "solve for \(x\), \[\frac{2x-2}{4}=3\]
btw what idiot writes \(f(x)=\frac{2x-2}{4}\) when it is just \(f(x)=\frac{x-1}{2}\) ? no matter you can solve in any case
Lool math is hard, man.
\[\frac{2x-2}{4}=3\\ 2x-2=12\] etc
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you good from there?
Yes! Thanks again!
yw
(I have one more)
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