Question

x^4-1=

Answer 1

It depends on the value of x.

Answer 2

I've never done this before

Answer 3

What is the question?

Answer 4

A. (x+1)(x-1)(x^2+1)
B. (x+1)^2(x-1)^2
C. (x+1)^3(x-1)^1
D. (x-1)^4

Answer 5

@jim_thompson5910

Answer 6

@campbell_st

Answer 7

well if you look at it, it's basically and equation that can be coverted to the difference of 2 squares

think about

\[x^4 - 1 = (x^2)^2 - 1\]

then it can be factored

\[(x^2 - 1)(x^2 + 1) \]

then the 1st binomial can be factored again... the 2nd can't be factored.

hope it helps