Question

Differentiate secxtanx

Answer 1

whats after (secxtanx)sec^2x

Answer 2

..........

Answer 3

use the product rule

u = sec(x) v = tan(x)

du/dx = sex(x)tan(x) dv/dx = sec^2(x)

so

\[\frac{dy}{dx}= u \times \frac{dv}{dx} + v \times \frac{du}{dx}\]

just substitute and simplify.

Hope it helps

Answer 4

oops should read

du/dx = sec(x)tan(x)