Question

solve initial value problem and find interval of validity to the solution yprime=x^2+3x+2/y-2 y(1)=4

Answer 1

\[y \prime = \frac{ x^2+3x+2 }{ y-2 } \]
\[y(1)=4\]

Answer 2

\[y \prime (y-2) = x^2+3x+2\]

Answer 3

and I go to integrate both sides but I'm having a brain fart.
would it be;
\[\frac{ y^2 }{ 2 }-2y+x=\frac{ x^3 }{ 3 }+\frac{ 3x^2 }{ 2 }+2x\]

Answer 4

+c* not x

Answer 5

SCRATCH finding interval of validity, read wrong question