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consider the function f(x)=sin(1/x) how do you think the function behaves near x=0? Explain your reasoning
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wiggles like crazy
It does but it would leave a hole a x=0 because the function has an asymptote there.
so how does it behave near 0?
how would i explain how the function behaves as it approaches 0? just that it curves a lot?
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You can say that it wobble more as x get closer to 0. http://www.math.washington.edu/~conroy/general/sin1overx/
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