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Solve for x: x+2/x-2=3/2 (x plus 2 over x minus 2 equals 3 over 2.) A. 2 B. 3 C. 8 D. 10
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As a start : cross multiply
\[\large \dfrac{x+2}{x-2} =\dfrac{3}{2}\] cross multiplying you get : \[\large 2(x+2) = 3(x-2)\] distribute and isolate x
so i would cross multiply 2 & 3 & 2&2?
i did cross multiplication step already you just need to distribute both sides and isolate x
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\[\large \large 2(x+2) = 3(x-2)\] \[\large \large 2x+4 = 3x-6\]
see if you can take it home from here
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