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Physics 9 Online
OpenStudy (anonymous):

Mr. Stephenson drives his car from Dallas to Town X, a distance of 437 km. The trip takes 7.27 hours. What is the average speed of this trip in meters per second (m/s)?

OpenStudy (anonymous):

\[v=\frac{ s }{ t }=\frac{ 437 }{ 7.27 }\approx60.1(km/h)\] One useful think is 1m/s=3.6km/h. Therefore, \[v=\frac{ 60.1 }{ 3.6 }\approx16.7(m/s)\]

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