Question

Algebra help? Question below.

Answer 1

\[\sum_{i=3}^{10} 2i-9\]

Answer 2

all you are being asked to do is add some terms after doing some substitution.

starting with the substitution

when i = 3 you get 2 x 3 - 9 = -3

i = 4 2 x 4 - 9 = -1

i = 5 2 x 5 - 9 = 1

just keep going, the last term is when i = 10

then just add all the answers together...

this is called sigma notation, which means to add terms

the bit on the bottom i = 3 tells you where to start, and the value on top, in this question its 10, tells you where it finishes...

Answer 3

I got 32. I think you just taught me how to do it better then the course! Thank you!