Question

Find all the solutions for the polynomials below. 4x^2+20=0

Answer 1

ok divide through by 4
x^2 + 5 = 0
x^2 = -5
there is no real number which has a negative square

the roots are 2 imaginary numbers

do you know what they are?

Answer 2

no

Answer 3

\(\large\tt \color{black}{x^2 = -5}\)

\(\large\tt \color{black}{x=\pm\sqrt{-5}=\pm\sqrt5\times i}\)


\(\large\tt \color{blue}{note~~that~~\sqrt{-1}=i}\)