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12x-1x+9=6x-21
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\[\frac{ 4x-1 }{ 3x+9 }=2x-7\]
\[4x-1=(2x-7)(3x+9)\]
\[4x-1=6x ^{2}-3x-63\]
\[0=6x ^{2}-7x-62\]
Oh sorry I mean the 1\3 as a fraction
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So what Im really asking is 12x-1x+9=6x-21
Then you can just combine all the x's and solve for x
11x+9=6x-21 5x=-30 x=-6
Oh okay thank you
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