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The widths (in meters) of a kidney-shaped swimming pool were measured at 3-meter intervals as indicated in the figure. Use the Midpoint Rule with n = 4 to estimate the area S of the pool if a1 = 9.3, a2 = 10.8, a3 = 10.2, a4 = 8.4, a5 = 7.5, a6 = 7.2, and a7 = 7.2.
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\[\Delta x=\frac{7.2-9.3}{4}=-.525\] this doesn't seem right to me
if psble take a screenshot of actual question/diagram and attach
can do
Notice that the widths of swimming pool were measured in 3-meter intervals
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yeah
So from left to right, the length of swimming pool would be : 3x8 = 24m
for n=4, you need to divide 24 by 4 : \[\large \Delta x = \dfrac{24}{4} = 6\]
and the midpoint values are : a_1, a_3, a_5, a_7
so 6(9.3+10.2+7.5+7.2)
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Looks good !
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